5p^2+35p=0

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Solution for 5p^2+35p=0 equation: 



5p^2+35p=0

a = 5; b = 35; c = 0;
Δ = b2-4ac
Δ = 352-4·5·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$


$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-35}{2*5}=\frac{-70}{10}
=-7
$


$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+35}{2*5}=\frac{0}{10}
=0
$

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